Problem detail · source-aware

Erdős Problem #1026: Monotonic Subsequence Sums

resolvedconfidence 70%

VibeMathed reports this item as resolved. VibeMath preserves that report as a source assertion and has not independently authored a plain-language mathematical explanation.

Precise statement

For a sequence of $n$ distinct reals, determine the largest constant $c$ such that some monotonic subsequence always has sum exceeding $(c-o(1))\cdot(1/\sqrt{n})$ times the total sum. Resolved as $c = 1$.

The source statement is reproduced for indexing with attribution. Mathematical correctness requires domain-expert or mechanical review. VibeMath has not independently audited statement fidelity, correctness, priority, or novelty.

What AI did

Aristotle, with GPT, Gemini and AlphaEvolve also contributing

Multiple AI systems contributed within an ordinary human mathematical collaboration rather than one model solving it outright; Aristotle produced and formally verified the winning proof in Lean, pinning down the sharp constant $c = 1$.

Provider: Harmonic / OpenAI / Google DeepMind · Prompt public: unknown · Independence: unknown

Verification boundary

lean verified statement audited

Formally verified in Lean. Documented firsthand by Terence Tao on his blog as a case study in AI-assisted collaboration, not an AI-alone result.

Correctness: supported · statement fidelity: audited · peer review: none

Timeline

  1. Terence Tao's blog

    VibeMathed reports this item as resolved. VibeMath preserves that report as a source assertion and has not independently authored a plain-language mathematical explanation.

Known method families

argument (source-reported)

Source-reported tools: argument.

Independent: unknown · difference confidence: 0

What remains uncertain

VibeMath has not independently audited the mathematical statement, proof, or novelty claim.

  • VibeMath has not independently verified the mathematical claim.
  • AI-attempt independence and training-data exposure are unknown unless explicitly documented.
  • VibeMath has not independently audited the mathematical statement, proof, or novelty claim.