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Precise statement
The Hessian conjecture $HC_n$ asks whether every polynomial $f$ with $\det \mathrm{Hess}(f) \in \mathbb{C}^\times$ has a polynomial gradient inverse. It is known for $n \le 3$, false for $n \ge 5$, and open exactly in dimension four, where it implies the plane Jacobian conjecture. Proved for every quartic polynomial in dimension four: the quartic case reduces to $f = P(x_1,x_2,x_3) + x_4 Q(x_1,x_2,x_3) + a x_4^2$ with $\deg Q \le 2$, and every constant-Hessian polynomial of this form has a polynomial gradient inverse.
The source statement is reproduced for indexing with attribution. Mathematical correctness requires domain-expert or mechanical review. VibeMath has not independently audited statement
fidelity, correctness, priority, or novelty.
What AI did
GPT-5.6 Sol, GPT-5.6 Luna, Claude Fable 5, DeepSeek V4 Pro
The acknowledgement credits four systems - GPT-5.6 Sol, GPT-5.6 Luna, Claude Fable 5 and DeepSeek V4 Pro - with exploring candidate arguments, adversarial proof review, algebraic checking and editorial assistance, with the author independently reviewing all arguments. No individual step is attributed, so the lower tier applies.
Checked by this site on 17 August 2026 against the paper's LaTeX (arXiv:2608.14217): the acknowledgement is verbatim as quoted, and the introduction's status summary (known for n <= 3 by Dillen and de Bondt, false for n >= 5, open for n = 4, HC_4 implies the plane Jacobian conjecture) matches the literature, including the n >= 5 counterexample recorded as this catalog's sibling entry. Sole-author preprint, days old, not checked here, no independent review.
VibeMathed reports this item as partial. VibeMath preserves that report as a source assertion and has not independently authored a plain-language mathematical explanation.
Known method families
argument (source-reported)
Source-reported tools: argument.
Independent: unknown · difference confidence: 0
What remains uncertain
VibeMath has not independently audited the mathematical statement, proof, or novelty claim.
VibeMath has not independently verified the mathematical claim.
AI-attempt independence and training-data exposure are unknown unless explicitly documented.
VibeMath has not independently audited the mathematical statement, proof, or novelty claim.